Partial Fractions

Integration Using Partial Fraction Decomposition

Partial fraction decomposition is the process of taking a rational function and decomposing it into simpler rational expressions which are easier to integrate.

We only use partial fractions if the rational function is proper. If

f(x)=\frac{p(x)}{q(x)}

then the degree of p(x) must be less than the degree of q(x).

Types of Partial Fraction Decompositions

FactorTerm in Partial Fraction
ax+b\frac{A}{ax+b}
(ax+b)^n

    \[ \frac{A_1}{ax+b} + \frac{A_2}{(ax+b)^2} +\cdots+ \frac{A_n}{(ax+b)^n}\]

Irreducible quadratic
ax^2+bx+c

    \[ \frac{Ax+B}{ax^2+bx+c} \]

Example

    \[ \int \frac{3x+5}{x^2-x-2}\,dx \]

Find

Factorise the denominator:

    \[ x^2-x-2=(x-2)(x+1) \]

Write

    \[ \frac{3x+5}{(x-2)(x+1)} = \frac{A}{x-2} + \frac{B}{x+1} \]

Multiplying through by

(x-2)(x+1):

    \[ 3x+5=A(x+1)+B(x-2) \]

Let x=-1:

    \[ 2=-3B \]

    \[ B=-\frac23 \]

Let x=2:

    \[ 11=3A \]

    \[ A=\frac{11}{3} \]

Hence

    \[ \frac{3x+5}{x^2-x-2} = \frac{11}{3(x-2)} - \frac{2}{3(x+1)} \]

Integrating:

    \[ \int\frac{3x+5}{x^2-x-2}\,dx = \int \left( \frac{11}{3(x-2)} - \frac{2}{3(x+1)} \right) dx \]

    \[ = \frac{11}{3}\ln|x-2| -\frac23\ln|x+1| +C \]

Example

Find

    \[ \int\frac{3x+2}{(x-1)^2}\,dx \]

Write

    \[ \frac{3x+2}{(x-1)^2} = \frac{A_1}{x-1} + \frac{A_2}{(x-1)^2} \]

Multiplying through by (x-1)^2:

    \[ 3x+2=A_1(x-1)+A_2 \]

Let x=1:

    \[ 5=A_2 \]

Let x=0:

    \[ 2=-A_1+5 \]

    \[ A_1=3 \]

Therefore

    \[ \int\frac{3x+2}{(x-1)^2}\,dx = \int \left( \frac3{x-1} + \frac5{(x-1)^2} \right) dx \]

    \[ = 3\ln|x-1| -\frac5{x-1} +C \]

Example

Find

    \[ \int \frac{2x-5} {(x-1)(x^2+1)} \,dx \]

Write

    \[ \frac{2x-5} {(x-1)(x^2+1)} = \frac{A}{x-1} + \frac{Bx+C}{x^2+1} \]

Multiplying through:

    \[ 2x-5 = A(x^2+1) + (Bx+C)(x-1) \]

Let x=1:

    \[ -3=2A \]

    \[ A=-\frac32 \]

Let x=0:

    \[ -5=-\frac32-C \]

    \[ C=\frac72 \]

Let x=-1:

    \[ -7=-3+\left(-B+\frac72\right)(-2) \]

    \[ -4=2B-7 \]

    \[ B=\frac32 \]

Hence

    \[ \int \frac{2x-5} {(x-1)(x^2+1)} \,dx = \frac12 \int \left( -\frac3{x-1} + \frac{3x}{x^2+1} + \frac7{x^2+1} \right) dx \]

    \[ = \frac12 \left( -3\ln|x-1| +\frac32\ln(x^2+1) +7\arctan(x) \right) +C \]

    \[ = -\frac32\ln|x-1| +\frac34\ln(x^2+1) +\frac72\arctan(x) +C \]

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