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Trigonometry Question

I don’t know where I found this question, but it does require algebra and problem solving (as well as right trig and Pythagoras)

From a point A, a lighthouse is on a bearing of 026^\circT and the top of the light house is at an angle of elevation of 20.25^\circ. From a point B, the lighthouse is on a bearing of 296^\cricT and the top of the lighthouse is at angle of elevation of 10.2^\circ. If A and B are 500 metres apart, find the height of the lighthouse.

Let’s draw a diagram.

Let the height of the lighthouse be h

We can find the angle between A, the lighthouse, and B by using the base triangle

The red line from L is parallel to the two north lines. Hence \theta=26^\circ+64^\circ=90^\circ (Alternate angles in parallel lines are congruent)

It’s a right triangle so we know

(1)   \begin{equation*}500^2=(AL)^2+(BL)^2\end{equation*}

We are going to use the other two triangles to find AL and BL


tan(20.25)=\frac{h}{AL}
AL=\frac{h}{tan(20.25)}

tan(10.2)=\frac{h}{BL}
BL=\frac{h}{tan(10.2)}

Substitute AL and BL into equation 1

    \begin{equation*}500^2=(\frac{h}{tan(20.25)})^2+(\frac{h}{tan(10.2)})^2\end{equation}

Solve for h.

    \begin{equation*}500^2=7.35h^2+30.89h^2=38.24h^2\end{equation}

    \begin{equation*}h^2=6538.3\end{equation}

    \begin{equation*}h=80.9m\end{equation}

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Filed under Algebra, Bearings, Pythagoras, Right Trigonometry, Solving Equations, Trigonometry